[limits at infinity][section 2]

(1.)   lim  (1/x4)           here is the problem
      x->0

=   
           

(2.)   lim  (1/x5)       here is the problem
       x->0

=   DNE   (does not exist)

 [because, the limit is different coming in from the left of

   0, as it is coming in from the right of 0]

(3.)   lim [1/(x - 5)3]         here is the problem
      x->5

=   DNE  (does not exist)

(4.)   lim  (x + x2)/(x2 + x3)      here is the problem
      x->0

=      lim (1 + x)/(x + x2)         divide thru by x, cancel

=      lim (1/x)(1 + x)/(1 + x)    factor

=     lim  (1/x)                    cancel
     x->0

=   DNE

(5.)   lim  (x - 4)/(x + 3)2
      x->-3

=  
   
                 
(6.)   lim   x/(1 + x)
       x->


=    1
         

                      _
(7.)    lim  [1/(1 - √x)]
       x->


=    0

(8.)   lim  (2x + 3)/(3x + 2)
     x->


=    2/3

(9.)   lim (5x - x2)/(3x + x2)
     x->


 =   -1

(10.)  lim  [2x2 + 3x + 5]
      x->
______________
            [3x2 - x + 2]

=  2/3